I think I know the answer to this question, based on reading a lot of the excellent posts here, but would like a little affirmation before setting off to do what I want to do.
I'm currently running Windows 7 RC (7100) and Vista x64 in a dual boot configuration. I have two SATA drives (0 and 1) running in RAID 0 as a single, logical 150 GB drive. The drive has two partitions - C: and F: Windows 7 is loaded on C: and Vista on F: Of the two OSes, Vista was installed first on F: (when C was an XP partition). C: was later upgraded from XP to Windows 7.
I want to delete the Vista partition and only boot in Windows 7. I believe I can do this by simply deleting the partition using the Windows 7 administrative tools and removing the bootmgr entry using EasyBCD. Why do I think this? I believe that the bootmgr is in the MBR of the logical drive that contains both the C: and F: partitions. Deleting the F: partition won't affect the MBR and with no other entry in the bootmgr, the computer will boot to C:
Am I correct or am I all wet?
Thx
-K2
I'm currently running Windows 7 RC (7100) and Vista x64 in a dual boot configuration. I have two SATA drives (0 and 1) running in RAID 0 as a single, logical 150 GB drive. The drive has two partitions - C: and F: Windows 7 is loaded on C: and Vista on F: Of the two OSes, Vista was installed first on F: (when C was an XP partition). C: was later upgraded from XP to Windows 7.
I want to delete the Vista partition and only boot in Windows 7. I believe I can do this by simply deleting the partition using the Windows 7 administrative tools and removing the bootmgr entry using EasyBCD. Why do I think this? I believe that the bootmgr is in the MBR of the logical drive that contains both the C: and F: partitions. Deleting the F: partition won't affect the MBR and with no other entry in the bootmgr, the computer will boot to C:
Am I correct or am I all wet?
Thx
-K2